-4000+2000/(1+x)^1=0

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Solution for -4000+2000/(1+x)^1=0 equation: 


D( x )

(x+1)^1 = 0

(x+1)^1 = 0

(x+1)^1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

2000/((x+1)^1)-4000 = 0

2000/(x+1)-4000 = 0

2000/(x+1)+(-4000*(x+1))/(x+1) = 0

2000-4000*(x+1) = 0

-4000*x-2000 = 0

(-4000*x-2000)/(x+1) = 0

(-4000*x-2000)/(x+1) = 0 // * x+1

-4000*x-2000 = 0

-4000*x-2000 = 0 // + 2000

-4000*x = 2000 // : -4000

x = 2000/(-4000)

x = -1/2

x = -1/2

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